I don't understand why assume that is a 1/1 probablity of S|R instead of R|R? Only ocurrs 1 state of S and in this state you don't know what is the prior state. Why assume that the prior state was S and not R?

asked 15 Nov '11, 23:35

apis3445's gravatar image

apis3445
162


P(S|R) is the probability that the day that follows a rainy day will be sunny.

It probably would have been clearer if he had written something like P(day_(t+1)=S | day_(t)=R)

link

answered 15 Nov '11, 23:39

L_McLean's gravatar image

L_McLean ♦
8.4k318

Ok thanks I was understanding wrong.

link

answered 16 Nov '11, 00:01

apis3445's gravatar image

apis3445
162

Glad I helped :)
(16 Nov '11, 00:06) L_McLean ♦ L_McLean's gravatar image
Your answer
toggle preview

Follow this Question via Email

Once you sign in you will be able to subscribe for any updates here

Q&A Editor Basics

  • to upload an image into your question or answer hit
  • to create bulleted or numbered lists hit or
  • to add a title or header hit
  • to section your text hit
  • to make a link clickable, surround it with <a> and </a> (for example, <a>www.google.com</a>)
  • basic HTML tags are also supported (for those who know a bit of HTML)
  • To insert an EQUATION you can use LaTeX. (backslash \ has to be escaped, so in your LaTeX code you have to replace \ with \\). You can see more examples and info here

powered by OSQA