How get the probality of (S|R) ?

0	I don't understand why assume that is a 1/1 probablity of S\|R instead of R\|R? Only ocurrs 1 state of S and in this state you don't know what is the prior state. Why assume that the prior state was S and not R? probability asked 15 Nov '11, 23:35 apis3445 16●2

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2 Answers:

1	P(S\|R) is the probability that the day that follows a rainy day will be sunny. It probably would have been clearer if he had written something like P(day_(t+1)=S \| day_(t)=R) link answered 15 Nov '11, 23:39 L_McLean ♦ 8.4k●3●16

0	Ok thanks I was understanding wrong. link answered 16 Nov '11, 00:01 apis3445 16●2 Glad I helped :) (16 Nov '11, 00:06) L_McLean ♦

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