# How get the probality of (S|R) ?

 0 I don't understand why assume that is a 1/1 probablity of S|R instead of R|R? Only ocurrs 1 state of S and in this state you don't know what is the prior state. Why assume that the prior state was S and not R? asked 15 Nov '11, 23:35 apis3445 16●3

 1 P(S|R) is the probability that the day that follows a rainy day will be sunny. It probably would have been clearer if he had written something like P(day_(t+1)=S | day_(t)=R) answered 15 Nov '11, 23:39 L_McLean ♦ 8.4k●3●18
 0 Ok thanks I was understanding wrong. answered 16 Nov '11, 00:01 apis3445 16●3 Glad I helped :) (16 Nov '11, 00:06) L_McLean ♦
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